Question

A political candidate has asked you to conduct a poll to
determine what percentage of people support her.

If the candidate only wants a 7% margin of error at a 99%
confidence level, what size of sample is needed?

Give your answer in whole people.

Answer #1

Solution,

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 7% = 0.07

At 99% confidence level

= 1 - 99%

= 1 - 0.99 = 0.01

/2
= 0.005

Z/2
= Z0.005 = 2.576

Sample size = n = (Z_{
/ 2} / E )^{2} *
* (1 -
)

= (2.576 / 0.07)^{2} * 0.5 * 0.5

= 338.56

**Sample size = n = 339**

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If the candidate only wants a 8% margin of error at a 99%
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Give your answer in whole people.

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