The amount of material used in making a custom sail for a
sailboat is normally distributed with a standard deviation of 64
square feet. For a random sample of 15 sails, the mean amount of
material used is 912 square feet. Which of the following represents
a 99% confidence interval for the population mean amount of
material used in a custom sail?
A. 912 ± 46.8
B. 912 ± 42.6
C. 912 ± 44.3
D. 912 ± 49.2
Level of Significance , α =
0.01
' ' '
z value= z α/2= 2.5758 [Excel
formula =NORMSINV(α/2) ]
Standard Error , SE = σ/√n = 64.0000 /
√ 15 = 16.524729
margin of error, E=Z*SE = 2.5758
* 16.52473 = 42.564881 =
42.6
B. 912 ± 42.6
Thanks in advance!
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