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In a simple random sample of 145 households, the sample mean number of personal computers was...

In a simple random sample of 145 households, the sample mean number of personal computers was 1.36 . Assume the population standard deviation is .48

(a) Construct a 98% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places.

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Answer #1

We have given that,              
              
Sample mean =1.36      
Population standard deviation=   0.48  
Sample size=145      
Level of significance =   1-0.98=0.02      
Z critical value (by using Z table)=2.326      
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