Question
In a simple random sample of 145 households, the sample mean number of personal computers was...
In a simple random sample of 145 households, the sample mean number of personal computers was 1.36 . Assume the population standard deviation is .48
(a) Construct a 98% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places.
Homework Answers
Answer #1
We have given that,
Sample mean =1.36
Population standard deviation= 0.48
Sample size=145
Level of significance = 1-0.98=0.02
Z critical value (by using Z table)=2.326
|
|
Not the answer you're looking for?
Similar Questions
A simple random sample of 40 items resulted in a sample mean of 30. The population...
A simple random sample of 40 items resulted in a sample mean of
30. The population standard deviation is σ = 20. a. Compute the 95%
confidence interval for the population mean. Round your answers to
one decimal place. Assume that the same sample mean was obtained
from a sample of 100 items. Provide a 95% confidence interval for
the population mean. Round your answers to two decimal places. What
is the effect of a larger sample size on the...
A random sample of 14 observations is used to estimate the population mean. The sample mean...
A random sample of 14 observations is used to estimate the
population mean. The sample mean and the sample standard deviation
are calculated as 158.4 and 30.10, respectively. Assume that the
population is normally distributed. [You may find it useful
to reference the t table.]
a. Construct the 90% confidence interval for the
population mean. (Round intermediate calculations to at
least 4 decimal places. Round "t" value to 3 decimal
places and final answers to 2 decimal places.)
b. Construct...
A simple random sample of size n equals 40 is drawn from a population. The sample...
A simple random sample of size n equals 40 is drawn from a
population. The sample mean is found to be x overbar equals 121.4
and the sample standard deviation is found to be s equals 12.4.
Construct a 99% confidence interval for the population mean.
The lower bound is ?. (Round to two decimal places as
needed.)
The upper bound is ?. (Round to two decimal places as
needed.)
A simple random sample of size nequals24 is drawn from a population that is normally distributed....
A simple random sample of size nequals24 is drawn from a
population that is normally distributed. The sample mean is found
to be x overbar equals 58 and the sample standard deviation is
found to be sequals10. Construct a 90% confidence interval about
the population mean. The 90% confidence interval is ( nothing,
nothing). (Round to two decimal places as needed.)
A simple random sample of size nequals17 is drawn from a population that is normally distributed....
A simple random sample of size nequals17 is drawn from a
population that is normally distributed. The sample mean is found
to be x overbar equals 61 and the sample standard deviation is
found to be sequals11. Construct a 95% confidence interval about
the population mean. The 95% confidence interval is ( nothing,
nothing). (Round to two decimal places as needed.)
A simple random sample of size n=15 is drawn from a population that is normally distributed....
A simple random sample of size n=15 is drawn from a population
that is normally distributed. The sample mean is found to be x
overbar=62 and the sample standard deviation is found to be s=19.
Construct a 95% confidence interval about the population mean.
The 95% confidence interval is (_,_).
(Round to two decimal places as needed.)
A simple random sample of 70 items resulted in a sample mean of 80. The population standard deviation is
A simple random sample of 70 items resulted in a sample mean of
80. The population standard deviation isσ = 15.(a)Compute the 95% confidence interval for the population mean.
(Round your answers to two decimal places.)to(b)Assume that the same sample mean was obtained from a sample of
140 items. Provide a 95% confidence interval for the population
mean. (Round your answers to two decimal places.)to(c)What is the effect of a larger sample size on the interval
estimate?A larger sample size...
According to recent surveys, 60% of households have personal computers. If a random sample of 180...
According to recent surveys, 60% of households have personal
computers. If a random sample of 180 households is selected, what
is the probability that more than 60, but fewer than 100, have a
personal computer. Use the normal approximation and express your
answer as a decimal. Please round to the nearest thousandth.
In a sample of 100 households, the mean number of hours spent on social networking sites...
In a sample of 100 households, the mean number of hours spent on
social networking sites during the month of January was 50 hours.
In a much larger study, the standard deviation was determined to be
6 hours. Assume the population standard deviation is the same. What
is the 98% confidence interval for the mean hours devoted to social
networking in January?
A
The 98% confidence interval ranges from 6 to 50 hours.
B
The 98% confidence interval ranges from...
{Exercise 8.3 (Algorithmic)} A simple random sample of 40 items resulted in a sample mean of...
{Exercise 8.3
(Algorithmic)}
A simple random sample
of 40 items resulted in a sample mean of 30. The population
standard deviation is σ = 15.
a.
Compute the 95% confidence interval for the population mean. Round
your answers to one decimal place.
Enter your answer using parentheses and a comma, in the form
(n1,n2). Do not use commas in your numerical answer (i.e. use 1200
instead of 1,200, etc.)
b.
Assume that the same sample mean was obtained from a...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 3 minutes ago
asked 10 minutes ago
asked 26 minutes ago
asked 47 minutes ago
asked 47 minutes ago
asked 48 minutes ago
asked 57 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago