What’s the probability of the following series of events; rolling a 7 on a fair set of 2 dice, followed by flipping a “heads” on a fair coin, followed by selecting the ace of spades from a fairly shuffled deck of 52 cards?
a. |
0.0371 |
|
b. |
0.0016 |
|
c. |
0.0351 |
|
d. |
0.0518 |
|
e. |
0.3333 |
1st event
sample space of two dice rolled simultaneously
(1,1) | (1,2) | (1,3) | (1,4) | (1,5) | (1,6) |
(2,1) | (2,2) | (2,3) | (2,4) | (2,5) | (2,6) |
(3,1) | (3,2) | (3,3) | (3,4) | (3,5) | (3,6) |
(4,1) | (4,2) | (4,3) | (4,4) | (4,5) | (4,6) |
(5,1) | (5,2) | (5,3) | (5,4) | (5,5) | (5,6) |
(6,1) | (6,2) | (6,3) | (6,4) | (6,5) | (6,6) |
Total sample space = 36
Sum of 7 can be seen by 6 rolls
Favourable outcomes (sum of 7) = 6
p(sum of 7) = 6/36 = 1/6
2nd event
while flipping a coin, we have two sample space=heads & tails
(2)
P(head) = 1/2
3rd event
shuffled deck of 52 cards
P(Ace of Spade) = 1/52
overall probability = (1/6)*(1/2)*(1/52) = 0.0016 Option B
please upvote, thanks
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