Question

Significane Level of a=0.05 is used for each hypothesis test and a confidence level of 95% is used for each confidence interval estimate.

A random sample of people who work regular 9-5 hours and a random sample of people who work shifts were asked how many hours of sleep they get per day on average. An appropriate F-Test was performed and it was found that the null hypothesis of the F-Test should be rejected. Can we infer that there is a difference in the number of hours people sleep depending on whether they work 9-5 or shifts?

Printout #:_______________________
H0:__________________________
H1:__________________________
p-value:_______________________
Conclusion: Accept H0 / Reject H0

Possible Data Sets (Print-Outs to choose from):

Analysis of variance (Amount):

Source		Sum of Squares	Mean Squares
		3462.363
	177	15070.775
Corrected Total	180	18533.138

T-test for two independent samples/ two-tailes tests:

95% confidence interval on the difference the means: ( 0.276 , 1.191 )

Fisher’s F-Test / Two-tailes test:

ratio	1.037
F oberserved value	1.037
F Critical value	2.979
DF1	14
DF2	14
p-value (two tailed)	0.947
alpha	0.05

Type l Sum of squares analysis (Var 1 ):

Source	DF	Sum of Sqaures	Mean Squares	F	pr > f
Q1	1	11.25	11.25	1.115	0.294
Q2	2	135.85	45.283	45.283	0.006
Q1*Q2	3	6.25	2.083	0.207	0.892

T-test for two independent samples / Two-tailes test:

Difference	0.733
t(observed value)	3.322
t(critival value)	2.074
DF	22
p-value	0.003
alpha	0.05

Z-test for two proportions / two-tailed test:

95% confidence interval on the difference the means: ( -0.025, 0.105 )

Type l sum of squares analysis:

Source	DF	Sum of Sqaures	Mean Squares	F	pr > f
Q1	4	616.421	154.105	4.714	0.002
Q2	19	3574.166	188.114	5.754	< 0.0001

T-test for two paired samples / upper tailed test:

Difference	0.583
t(observed value)	1.023
t(critival value)	1.796
DF	11
p-value	0.164
alpha	0.05

Z-test for two proportions / upper-tailed test:

Difference	0.04
z(observed value)	1.2
z(critival value)	1.645
p-value	0.115
alpha	0.05

Answer 1

Let

The average hour sleep by the people who work 9 to 5 =

The average number of hour sleep by people who work on shifts =

now we have to check it is Same or different

so the null hypothesis will be

As we check all the values we find that the appropriate p value will be For two tailed T test

p=0.003

So According to question as we have rejected the null hypothesis that means the means are not equal and the means are representing the sleeping hour of the two group

so we can say that number of hour people sleeping is dependent on whether they working 9-5 or in shift