Question

Suppose the average size of a new house built in a certain county in 2006 was

2,271

square feet. A random sample of

30

new homes built in this county was selected in 2010. The average square footage was

2,187,

with a sample standard deviation of

220

square feet.

a. |
Using
alphaαequals=0.10, does this sample provide enough evidence to conclude that the average house size of a new home in the county has changed since 2006? |

b. |
Use technology to determine the p-value for this test. |

a. Determine the null and alternative hypotheses. Choose the correct answer below.

A.

Upper H 0H0:

μ=2,271

and

Upper H 1H1:

μ≠2,271

B.

Upper H 0H0:

μ≠2,271

and

Upper H 1H1:

μ=2,271

C.

Upper H 0H0:

μ=2,271

and

Upper H 1H1:

μ>2,271

D.

Upper H 0H0:

μ≥2,271

and

Upper H 1H1:

μ<2,271

Determine the critical value(s).

The critical value(s) is(are)

nothing.

(Round to three decimal places as needed. Use a comma to separate answers as needed.)

Determine the test statistic,

t Subscript x overbartx.

t Subscript x overbartxequals=nothing

(Round to two decimal places as needed.)

What conclusion should be drawn? Choose the correct answer below.

A.

Suppose the average size of a new house built in a certain county in 2006 was

2 comma 2712,271

square feet. A random sample of

3030

new homes built in this county was selected in 2010. The average square footage was

2 comma 1872,187,

with a sample standard deviation of

220220

square feet.

a. |
Using
alphaαequals=0.100.10, does this sample provide enough evidence to conclude that the average house size of a new home in the county has changed since 2006? |

b. |
Use technology to determine the p-value for this test. |

a. Determine the null and alternative hypotheses. Choose the correct answer below.

A.

Upper H 0H0:

mu equals 2 comma 271μ=2,271

and

Upper H 1H1:

mu not equals 2 comma 271μ≠2,271

B.

Upper H 0H0:

mu not equals 2 comma 271μ≠2,271

and

Upper H 1H1:

mu equals 2 comma 271μ=2,271

C.

Upper H 0H0:

mu equals 2 comma 271μ=2,271

and

Upper H 1H1:

mu greater than 2 comma 271μ>2,271

D.

Upper H 0H0:

mu greater than or equals 2 comma 271μ≥2,271

and

Upper H 1H1:

mu less than 2 comma 271μ<2,271

Determine the critical value(s).

The critical value(s) is(are)

nothing.

(Round to three decimal places as needed. Use a comma to separate answers as needed.)

Determine the test statistic,

t Subscript x overbartx.

t Subscript x overbartxequals=nothing

(Round to two decimal places as needed.)

What conclusion should be drawn? Choose the correct answer below.

A.

A.

RejectReject

the null hypothesis. The data

provideprovide

sufficient evidence to conclude that the average house size has changed since 2006.

B.

Do not rejectDo not reject

the null hypothesis. The data

provideprovide

sufficient evidence to conclude that the average house size has changed since 2006.

C.

RejectReject

the null hypothesis. The data

do not providedo not provide

sufficient evidence to conclude that the average house size has changed since 2006.

D.

Do not rejectDo not reject

the null hypothesis. The data

do not providedo not provide

sufficient evidence to conclude that the average house size has changed since 2006.

b. Use technology to determine the p-value for this test. What is the p-value?

p-valueequals=nothing

(Round to three decimal places as needed.)

Answer #1

Suppose the average size of a new house built in a certain
county in 2006 was 2 comma 279 square feet. A random sample of 25
new homes built in this county was selected in 2010. The average
square footage was 2 comma 198, with a sample standard deviation
of 229 square feet
a. Using alphaequals0.01, does this sample provide enough
evidence to conclude that the average house size of a new home in
the county has changed since 2006?...

According to a survey, people in a certain country ate an
average of
205 meals in restaurants in 2001. The data in the accompanying
table show the number of meals eaten in restaurants as determined
from a random sample of people in this country in 2009. Complete
parts (a) through (d) below.
LOADING... Click the icon to view the data table.
213
132
199
344
141
80
183
309
56
197
168
310
95
231
266
292
226
316
206...

A politician claims that the mean salary for managers in his
state is more than the national? mean, ?81,000. Assume the the
population is normally distributed and the population standard
deviation is ?$9000. The salaries? (in dollars) for a random sample
of 30 managers in the state are listed. At ?=0.1?, is there enough
evidence to support the? claim? Use technology
97,114
79,642
71,801
88,955
76,739
75,497
95,067
95,523
94,043
80,146
96,239
90,034
94,963
76,493
83,155
92,796
71,584
94,954
81,307...

Listed below are systolic blood pressure measurements (mm Hg)
taken from the right and left arms of the same woman. Assume that
the paired sample data is a simple random sample and that the
differences have a distribution that is approximately normal. Use
a
0.050.05
significance level to test for a difference between the
measurements from the two arms. What can be concluded?
Right arm
152152
148148
115115
129129
136136
Left arm
172172
168168
177177
148148
149149
In this example,...

Q30. YouTube would like to test the hypothesis that the average
length of an online video watched by a user is more than 8 minutes.
A random sample of 36 people watched online videos that averaged
8.7 minutes in length. It is believed that the population standard
deviation for the length of online videos is 3 minutes.
a. The p-value for this hypothesis test would be _______.
A.
0.9192
B.
0.5910
C.
0.0808
D.
0.4090
b. If YouTube uses an...

A 2010 survey by a reputable automotive website found that
6868?%
of vehicle owners avoided automotive maintenance and repairs.
Suppose a company would like to perform a hypothesis test to
challenge this finding. From a random sample of
110110
vehicle? owners, it was found that
8484
avoid maintenance repairs. Using
alpha?equals=0.020.02?,
answer parts a and b below.
a. What conclusions can be drawn concerning the
proportion of vehicle owners who avoid automotive maintenance and?
repairs?
Determine the null and alternative...

Settings
Accessibility
+
On-Screen Keyboard
+
About
+
A personnel director in a particular state claims that the mean
annual income is greater in one of the state's counties (county A)
than it is in another county (county B). In County A, a random
sample of
1818
residents has a mean annual income of
$ 40 comma 100$40,100
and a standard deviation of
$ 8900$8900.
In County B, a random sample of
88
residents has a mean annual income of...

Consider the data in the table collected from four independent
populations.
Sample
1
Sample
2
Sample
3
Sample
4
a) Calculate the total sum of squares (SST).
b) Partition the SST into its two components, the sum of
squares between (SSB) and the sum of squares within (SSW).
44
1414
2121
44
77
1111
2222
33
88
1717
2020
1111
66
1313
c) Using
alphaαequals=0.050.05,
what conclusions can be made concerning the population
means?
LOADING...
Click the icon to view...

According to research, holiday shoppers spent an average of
$372 over a holiday weekend in 2008. The accompanying data show
the amount spent by a random sample of holiday shoppers during the
same weekend in 2009. Complete parts a and b below.
data table:
$429
$271
$375
$235
$225
$214
$356
$433
$385
$396
$316
$66
$414
$431
$381
$284
a. Retailers were concerned that the recent economic downturn
was going to affect holiday sales. Does this sample support these...

The lengths of time? (in years) it took a random sample of
3232
former smokers to quit smoking permanently are listed. Assume
the population standard deviation is
4.24.2
years. At
alpha?equals=0.060.06?,
is there enough evidence to reject the claim that the mean time
it takes smokers to quit smoking permanently is
1414
?years? Complete parts? (a) through? (e).
21.621.6
21.721.7
20.720.7
7.47.4
21.121.1
14.214.2
12.812.8
15.215.2
10.410.4
16.216.2
15.515.5
20.320.3
16.216.2
17.517.5
19.419.4
13.513.5
20.320.3
20.820.8
10.110.1
15.215.2
10.310.3
22.222.2...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 12 minutes ago

asked 16 minutes ago

asked 16 minutes ago

asked 18 minutes ago

asked 21 minutes ago

asked 24 minutes ago

asked 25 minutes ago

asked 45 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago