|Item||Group 1||Group 2||Group 3|
a. Conduct a one-way analysis of variance on the data assuming the populations have equal variances and the populations are normally distributed. Use alpha = 0.05.
b. If warranted, use the Tukey-Kramer procedure to determine which populations have different means. Use an alpha level of 0.05.
a) One Way ANOVA:
and (Atleast one is not equal)
Significant value= 0.05
The test statistic:
The test statistic is significant and rejects H0. There is sufficient evidence to support the claim that there is statistical difference between sample means.
b) Tukey's mean difference:
To be non significant:
Mean difference between 1 and 2: |14-16.75|= 2.75
|M1-M2| > T is significant.
Mean difference between 1 and 3: |M1-M3|= 1.333
|M1-M2| < T is not significant.
Mena difference between 2 and 3: |M2-M3|= 1.41667
|M2-M3| < T is not significant.
Group1 and 2 are significantly different.
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