Question

Item |
Group 1 |
Group 2 |
Group 3 |

1 | 14 | 17 | 17 |

2 | 13 | 16 | 14 |

3 | 12 | 16 | 15 |

4 | 15 | 18 | 16 |

5 | 16 | 14 | |

6 | 16 |

a. Conduct a one-way analysis of variance on the data assuming the populations have equal variances and the populations are normally distributed. Use alpha = 0.05.

b. If warranted, use the Tukey-Kramer procedure to determine which populations have different means. Use an alpha level of 0.05.

Answer #1

Groups | Count | Sum | Average | Variance |

Group 1 | 5 | 70 | 14 | 2.5 |

Group 2 | 4 | 67 | 16.75 | 0.916667 |

Group 3 | 6 | 92 | 15.33333 | 1.466667 |

a) One Way ANOVA:

and (Atleast one is not equal)

Significant value= 0.05

The test statistic:

Grand mean:

P-value: 0.025853

The test statistic is significant and rejects H0. There is sufficient evidence to support the claim that there is statistical difference between sample means.

b) Tukey's mean difference:

To be non significant:

Mean difference between 1 and 2: |14-16.75|= 2.75

|M1-M2| > T is significant.

Mean difference between 1 and 3: |M1-M3|= 1.333

|M1-M2| < T is not significant.

Mena difference between 2 and 3: |M2-M3|= 1.41667

|M2-M3| < T is not significant.

Group1 and 2 are significantly different.

you use critical range = 31.369 for all (the sample sizes are
equal).
Conduct the Tukey- Kramer procedure with alpha= 0.05 level,
q0.95 = 3.38 (from Stundentized range table).
The sample means(average) are given in the table below.
Summary
Groups
Count
Average
Variance
City 1
30
236.2393
334.11
City 2
30
344.0701
2201.818
City 3
30
201.503
2215
What is your conclusion

Cork price: 16 10 15 10 17 11 14 13 11 14 11 16 18 16 10 17 14
14 16 7 10 12 19 15 16 14 9 12 21 13 10 16 12 16 13 17 17 13 14 18
11 12 15 16 13 18 16 17 12 12 14 9 11 14 19 13 11 17 11 13 15 14 18
18 18 12 10 11 13 14 11 14 18 13 13 19 17 14...

Given two independent random samples with the following
results:
n1=17
x‾1=185
s1=22
n2=12
x‾2=150
s2=15
Use this data to find the 98%
confidence interval for the true difference between the
population means. Assume that the population variances are not
equal and that the two populations are normally distributed.
Step 1 of 3 : Find the critical value that should be
used in constructing the confidence interval. Round your answer to
three decimal places.

11. (1 pt).Consider the following data from two
independent groups:
Liberals: 2, 1, 3, 2
Conservatives: 4, 3, 3, 5, 2, 4
Calculate s^2 for each group.
12. (1 pt). For the data in Problem 11, calculate dfX,
dfY, and dftotal.
13. (1 pt). For the data in Problem 11, determine the
critical values for t, assuming a two-tailed test with an alpha of
0.05
14. (1 pt). For the data in Problem 11, calculate the
pooled variance, spooled2.
15....

Inferential Statistics
Chapter 16 Data Set 1. a group of participants who took a timed
test. The data are the average amount of time the participants took
on each item (Time) and the number of guesses it took to get each
item correct (Correct). This is a one tailed test, using p value
Examine the relationship between “Time” and “correct”. Look at all
the tables generated by a statistical analysis that you need to
discuss as the main scientific concept....

Given two independent random samples with the following
results:
n1=7
x‾1=129
s1=14
n2=14
x‾2=159
s2=24
Use this data to find the 95% confidence interval for the true
difference between the population means. Assume that the population
variances are not equal and that the two populations are normally
distributed.
Step 1 of 3:
Find the point estimate that should be used in constructing the
confidence interval.
Step 2 of 3:
Find the margin of error to be used in constructing the...

The following three independent random samples are obtained from
three normally distributed populations with equal variance. The
dependent variable is starting hourly wage, and the groups are the
types of position (internship, co-op, work study).
Group 1: Internship
Group 2: Co-op
Group 3: Work Study
10.5
8.25
12.5
10.75
9.5
13
12.25
10.5
11.75
15
12.75
10.5
11
11.75
13.75
12
10
12.75
14.25
12
13.25
Use technology to conduct a one-factor ANOVA to determine if the
group means are...

Returns
Year
X
Y
1
17
%
22
%
2
31
32
3
12
16
4
–
24
–
29
5
10
23
Using the returns shown above, calculate the arithmetic average
returns, the variances, and the standard deviations for X and Y.
Fill in the table below. (Do not round intermediate
calculations. Enter your average return and standard deviation as a
percent rounded to 2 decimal places, e.g., 32.16, and round the
variance to 5 decimal places, e.g., .16161.)...

Lab Group
Tube Number
Control
Protein
Glucose
1
1
0
2
6.9
2
0
2
3
2
1
1
0
18
2
0
0
15
3
1
3
1
14
2
3
1
15
4
1
1
2
13
2
0
0
16
5
1
4
2
11
2
4
1
16
6
1
0
3
3
2
1
3
4
SUM
17
17
134.9
MEAN
1.4
1.4
11.24
1/2 STAN DEV
FILL IN THE CHART WITH THE THREE 1/2...

1. The following data were obtained in a four-group study:
Group1
Group 2
Group 3
Group 4
6
6
3
5
5
9
7
3
7
9
6
1
5
4
3
4
3
5
4
3
4
6
7
5
(a) Are the four group means significantly different from each
other?
(b) Suppose all pairwise comparisons were investigated. If the
αΣ is maintained at the level of 0.05, is the difference between
the means of groups 2 and 4...

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