Question

A research company recently surveyed 8217 adults in one country about reform of the country's senate. Of these, 33% answered "Yes" to the question "Do you support abolishing the senate?". What is the margin of error for a 90% confidence interval for the population proportion based on this sample?

Answer #1

Solution :

Given that,

Point estimate = sample proportion = = 0.33

1 - = 1 - 0.33 = 0.67

Z/2 = 1.645

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.645 * (((0.33 * 0.67) / 8217)

**Margin of error** = **E =
0.009**

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