A research company recently surveyed 8217 adults in one country about reform of the country's senate. Of these, 33% answered "Yes" to the question "Do you support abolishing the senate?". What is the margin of error for a 90% confidence interval for the population proportion based on this sample?
Solution :
Given that,
Point estimate = sample proportion = = 0.33
1 - = 1 - 0.33 = 0.67
Z/2 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.33 * 0.67) / 8217)
Margin of error = E = 0.009
Get Answers For Free
Most questions answered within 1 hours.