Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 119 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.
Probability that fewer than 30 voted
Solution :
Given that,
p = 0.22
q = 1 - p =1 - 0.22=0.78
n = 119
Using binomial distribution,
Mean = = n * p = 119 * 0.22=26.18
Standard deviation = = n * p * q = 119 *0.22 * 0.78=4.5189
Using continuity correction ,
P( X <29.5) = P(x - ) / < (29.5 - 26.18) / 4.5189)
= P(z < 0.73)
Probability = 0.7673
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