Use technology to construct the confidence intervals for the population variance sigmasquared and the population standard deviation sigma. Assume the sample is taken from a normally distributed population. c=0.95, s=34, n=16
Solution :
Given that,
s = 34
Point estimate = s2 = 1156
2R = 2/2,df = 27.488
2L = 21 - /2,df = 6.262
The 95% confidence interval for 2 is,
(n - 1)s2 / 2/2 < 2 < (n - 1)s2 / 21 - /2
(15)(1156) / 27.488 < 2 < (15)(1156) / 6.262
630.81 < 2 < 2769.04
(630.81 , 2769.04)
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