Question

A manufacturer of a Pharmaceutical claims that their pain killer pills have 5 mg of Codeine....

A manufacturer of a Pharmaceutical claims that their pain killer pills have 5 mg of Codeine. Their research quality control manager takes a random sample of 20 pills. She calculates the sample average to be 4.238 mg. with a standard deviation of .217 lb. At the .05 level of significance, is the manufacturer correct?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A manufacturer of a Pharmaceutical claims that their pain killer pills have 5 mg of Codeine....
A manufacturer of a Pharmaceutical claims that their pain killer pills have 5 mg of Codeine. Their research quality control manager takes a random sample of 20 pills. She calculates the sample average to be 4.227 mg. with a standard deviation of .217 lb. At the 0.1 level of significance, is the manufacturer correct?
1. You work for the FTC.  A manufacturer of detergent claims that the mean weight of detergent...
1. You work for the FTC.  A manufacturer of detergent claims that the mean weight of detergent is 4.25 lb.  You take a random sample of 64 containers.  You calculate the sample average to be 4.238 lb. with a standard deviation of .127 lb.  At the .05 level of significance, is the manufacturer correct? 2. Is the average capacity of batteries less than 120 ampere-hours?  A random sample of 49 batteries had a mean of 118.47 and a standard deviation of 3.66.  Assume a normal distribution....
A pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%. It...
A pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%. It is known that from a particular production run impurity con- centrations follow a normal distribution with a standard deviation of 0.4%. A random sample of 64 pills from a production run was checked, and the sample mean impurity concentration was found to be 3.07%. a. Test at the 5% level the null hypothesis that the population mean impurity concentration is 3% against the alternative...
The manufacturer of a new cigarette claims that the average tar content per cigarette is 10.0 mg
The manufacturer of a new cigarette claims that the average tar content per cigarette is 10.0 mg. The US Center for Smoking Research believes the tar content percigarette is greater than 10 mg and wishes to conduct a study to support their claim. Theytake a random sample of 25 cigarettes from the production line and find an average of 10.20mg of tar/cigarette and a standard deviation of .5 mg. Can the manufacturer’s claim berefuted at the 0.01 level of significance?A....
a manufacturer considers his production process to be out of control when defects exceed 5%. in...
a manufacturer considers his production process to be out of control when defects exceed 5%. in a random sample of 67 items the defect rate is 5.4% but the manager claims that this is only a sample fluctuation and production is not really out of control. at the 7% level of significance use the o value method to test the manager's claim.
We have these hypotheses: H0: the amount of active ingredient in a pharmaceutical pill is 5...
We have these hypotheses: H0: the amount of active ingredient in a pharmaceutical pill is 5 mg H1: the amount is below 5 mg We can take a random sample of 40 such pills and find the amount of active ingredient in them, and let the sample average be x-bar. We also know that the standard deviation of the amount of active ingredient is 0.3 mg. If H0 is right, what is the (approximate) distribution of ( x-bar minus 5)...
A manufacturer claims that his television will have an average lifetime of at least 5 years....
A manufacturer claims that his television will have an average lifetime of at least 5 years. The standard deviation is 8 months. 64 sets were selected at random and their average lifetime was found to be 59 months. Is the manufacturer correct? Use α = 0.025. (If you used TI-83 please include calculations )
Please explain well! No shortcuts! 8. A manufacturer claims that his television will have an average...
Please explain well! No shortcuts! 8. A manufacturer claims that his television will have an average lifetime of at least five years. 81 televisions are selected at random, and their average lifetime was found to be 62 months, with a standard deviation of 7 months. Is the manufacturer correct? Use the p-value method with α = .05. Hint: work in months, not years. State your hypotheses: Calculate the test statistic: Find the p-value: State your decision: Write your conclusion:
A manufacturer of pharmaceutical products analyzes a specimen from each batch of a product to verify...
A manufacturer of pharmaceutical products analyzes a specimen from each batch of a product to verify the concentration of the active ingredient. The chemical analysis is not perfectly precise, but the company wants to know the true mean concentration. The laboratory analyzes each specimen 40 times and reports the sample mean concentration to be 0.8404 and the sample standard deviation to be 0.0420. 1. The manager of the research team claims that the true mean concentration is 0.88. Based on...
A manufacturer of pharmaceutical products analyzes a specimen from each batch of a product to verify...
A manufacturer of pharmaceutical products analyzes a specimen from each batch of a product to verify the concentration of the active ingredient. The chemical analysis is not perfectly precise, but the company wants to know the true mean concentration. The laboratory analyzes each specimen 40 times and reports the sample mean concentration to be 0.8404 and the sample standard deviation to be 0.0420. 1. The manager of the research team claims that the true mean concentration is 0.88. Based on...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT