If X~N, p( X > 10) is .16 and the mean of X is 5, what is the SD of X ?
Solution:-
Given that,
mean = = 5
x = 10
Using standard normal table,
P(Z > z) = 0.16
= 1 - P(Z < z) = 0.16
= P(Z < z) = 1 - 0.16
= P(Z < z ) = 0.84
= P(Z < 1.0 ) = 0.84
z = 1.0
Using z-score formula,
x = z * +
10 = 1.0 * + 5
= 10 - 5 / 1.0
= 5
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