Question

Using the data below, calculate the correlation between temperature and growth rate for these samples. Round your answer to 3 decimal place.

Temperature (C)	Growth Rate (divisions per hour)
2.6	854
1.4	200
1.6	354
1.9	395
2.2	401
2.8	590
2.2	587
2	465
2.3	450
2.5	456
2	560
2.5	932
2.8	835
2.6	789
2.4	660
2.1	615
1.8	589
2.2	532
2.3	541
2.1	550

(a) The correlation coefficient r = [a] (report your answer to 3 decimal places)

(b) The ALTERNATEl hypothesis is [b] (answer A or B)

(A) ρ = 0 ;

(B)  ρ ≠ 0

(c) calculated t value is [c] (report your answer to 3 decimal places)

(d) Degree of freedom = [d]

(e) critical t value at alpha =0.05 = [e]

(f) Do we reject or fail to reject the null hypothesis?

Answer: [f] (reject or fail to reject)

Answer 1

	ΣX	ΣY	Σ(x-x̅)²	Σ(y-ȳ)²	Σ(x-x̅)(y-ȳ)
total sum	44.3	11355	2.6255	624907.8	941.38
mean	2.22	567.75	SSxx	SSyy	SSxy

correlation coefficient ,    r = Sxy/√(Sx.Sy) =   0.735

...............

The ALTERNATEl hypothesiS:

(B)  ρ ≠ 0

...............

correlation , r=   0.7349  
t-test statistic = r*√(n-2)/√(1-r²) =        4.598
DF=n-2 =   18

critical t-value =    2.1009

Decison: TEST stat > critical value , So, Reject Ho  

...................

THANKS

revert back for doubt

please upvote