5 cards out of 52 can be chosen in ways.
a) P[Exactly 3 clubs and 1 spade] = [ 3 clubs from 13 , 1 spade from 13 , 1 from 26 non club non spade cards]
b) P[ No aces] =
and P[ exactly one ace] =
SO, P[At least 2 aces] = 1- P[no ace] - P[exactly one ace ] = 1- 0.6588-0.2995 = 0.0417
c) P[All from same suit] = [ 4 different suits, choose 1 , and then choose 5 cards of 13 cards of that suit]
d) P[[3 from one suit 2 from different suit ] =
e) P[ no spade ] =
P[ exactly one spade] =
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