An article published in the Washington Post claims that 45 percent of all Americans have brown eyes. A random sample of n = 82 college students students found 30 who had brown eyes.
Consider testing ?0:?=.45
??:?≠.45
(a) The test statistic is z =
(b) P-value =
Given : n=82 , X=30
The estimate of the sample proportion is ,
The null and alternative hypothesis is ,
The test is two-tailed test.
(a) The test statistic is ,
(b) The p-value is ,
p-value=
; From standard normal distribution table
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