Coffee and Depression. Researchers conducted a study investigating the relationship between caffeinated coffee consumption and risk of depression in women. They collected data on 50,739 women free of depression symptoms at the start of the study in the year 1996, and these women were followed through 2006. The researchers used questionnaires to collect data on caffeinated coffee consumption, asked each individual about physician- diagnosed depression, and also asked about the use of antidepressants. The table below shows the distribution of incidences of depression by amount of caffeinated coffee consumption.
Coffee |
≤ 1 |
2-6 |
1 |
2-3 |
≥ 4 |
||
Consumption |
cup/week |
cups/week |
cup/day |
cups/day |
cups/day |
Total |
|
Clinical |
Yes |
670 |
373 |
905 |
564 |
95 |
2,607 |
depression |
No |
11,545 |
6,244 |
16,329 |
11,726 |
2,288 |
48,132 |
Total |
12,215 |
6,617 |
17,234 |
12,290 |
2,383 |
50,739 |
What hypotheses are appropriate for evaluating if there is an association between coffee intake and depression?
Select one:
What proportion of the women from this study ended up suffering from depression?
What proportion of the women from this study never suffered from depression?
Calcuate the expected number that correspons to the observed number 95
Only with your number from the question above and the number 95,
perform the operation
(O−E)^2 /E
How many degrees of freedom are there in this situation?
The test statistic is χ2=20.93χ2=20.93 What is the p-value?
Select one:
Use your results to evaluate the hypotheses from the problem above
Select one:
One of the authors of this study was quoted on the NYTimes as saying it was “too early to recommend that women load up on extra coffee” based on just this study. Do you agree with this statement? Explain your reasoning
1)
H0:Caffeinated coffee consumption and depression in women are independent.
HA: Caffeinated coffee consumption and depression in women are dependent/associated.
2)
proportion of the women from this study ended up suffering from depression =48132/50739 =0.9486
3)
expected number =row total*column total/grand total =(2607*2383)/50739 =122.44
(O−E)^2 /E =(95-122.44)^2/122.44=6.150
4)
degree of freedom =(row-1)*(column-1) =(2-1)*(5-1)=4
5) less than 0.01
6)
Since p<α we reject the null hypothesis and accept the alternative
since from given data we can not conclude that load up on extra coffee decrease prevalence of depression.
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