A Statistics instructor is trying to figure out the percentage
of students that still
listen to ”Nirvana”. The instructor is pretty out of touch, so he
doesn’t have a prior percentage of students who listen to ”Nirvana”
that he can use. How many students should the Statistics instructor
sample if he wants to be within 5.5% of the actual percentage of
students who listen to Nirvana, using a 95% confidence level. ( For
the z value round it to two decimal places)
Solution,
Given that,
= 1 -
= 0.5
margin of error = E = 0.055
At 95% confidence level
= 1 - 95%
= 1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.96
sample size = n = (Z / 2 / E )2 *
* (1 -
)
= (1.96 / 0.055)2 * 0.5 * 0.5
= 317.49
sample size = n = 318
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