Weights (X) of men in a certain age group have a normal distribution with mean μ = 190 pounds and standard deviation σ = 20 pounds. Find each of the following probabilities. (Round all answers to four decimal places.)
(a) P(X ≤ 220) = probability the weight of a
randomly selected man is less than or equal to 220 pounds.
(b) P(X ≤ 165) = probability the weight of a
randomly selected man is less than or equal to 165 pounds.
(c) P(X > 165) = probability the weight of a
randomly selected man is more than 165 pounds.
Solution :
Given that ,
mean = = 190
standard deviation = = 20
a) P(x 220)
= P[(x - ) / (220 - 190) / 20]
= P(z 1.50)
Using z table,
= 0.9332
b) P(x 165)
= P[(x - ) / (165 - 190) / 20]
= P(z -1.25)
Using z table,
= 0.1056
c) P(x > 165 ) = 1 - p( x< 165)
=1- p P[(x - ) / < (165 - 190) / 20]
=1- P(z < -1.25)
Using z table,
= 1 - 0.1056
= 0.8944
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