The following hypotheses are given.
H0: p ≤ 0.45
H1: p > 0.45
A sample of 140 observations revealed that
= 0.35. At the 0.10 significance level, can the null hypothesis be rejected?
a. State the decision rule. (Round the final answer to 3 decimal places.)
(Click to select) Reject Not reject H0 and (Click to select) and accept and reject H1 if z > or z < .
b. Compute the value of the test statistic. (Round the final answer to 2 decimal places.)
Value of the test statistic
c. What is your decision regarding the null hypothesis?
(Click to select) Not rejected Rejected H0
a. State the decision rule.
We are given
α = 0.10
Test is an upper tailed test.
So, critical Z value is given as below:
Z = 1.282
Reject H0 if z > 1.282.
b. Compute the value of the test statistic.
Test statistic formula is given as below:
Z = (p̂ - p)/sqrt(pq/n)
We are given
p̂ = 0.35
p = 0.45
q = 1 - p = 1 - 0.45 = 0.55
n = 140
Z = (0.35 - 0.45)/sqrt(0.45*0.55/140)
Z = -2.37835
Test statistic = -2.38
c. What is your decision regarding the null hypothesis?
For this test, we have
Test statistic = -2.38 < Critical value = 1.282
So, we do not reject the null hypothesis
Answer: Not rejected H0
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