Question

E) Suppose that males between the ages of 40 and 49 eat on average 104.7 g of fat every day with a standard deviation of 4.43 g. The amount of fat a person eats is not normally distributed but it is relatively mound shaped.

Find the probability that a sample mean amount of daily fat intake for 38 men age 40-59 is more than 98 g. Round to four decimal places.

P(x̄ > 98) =

Find the probability that a sample mean amount of daily fat intake for 38 men age 40-59 in the U.S. is less than 94 g. Round to four decimal places.

P(x̄ < 94)= F)

C)Suppose the mean cholesterol levels of women age 45-59 is 5.4 mmol/l and the standard deviation is 1 mmol/l. Assume that cholesterol levels are normally distributed.

Find the probability that a woman age 45-59 has a cholesterol level above 6 mmol/l (considered a high level). Round to four decimal places.

P(x > 6) =

Suppose doctors decide to test the woman’s cholesterol level again and average the two values.

Find the probability that this woman’s mean cholesterol level for the two tests is above 6 mmol/l. Round to four decimal places.

P(x̄ > 6) =

Suppose doctors being very conservative decide to test the woman’s cholesterol level a third time and average the three values. Find the probability that this woman’s mean cholesterol level for the three tests is above 6 mmol/l. Round to four decimal places.

P(x̄ > 6) = g)

Suppose the mean cholesterol levels of women age 45-59 is 5.4 mmol/l and the standard deviation is 1 mmol/l. Assume that cholesterol levels are normally distributed. Find the probability that a woman age 45-59 has a cholesterol level above 6 mmol/l (considered a high level). Round to four decimal places.

P(x > 6) =

Suppose doctors decide to test the woman’s cholesterol level again and average the two values. Find the probability that this woman’s mean cholesterol level for the two tests is above 6 mmol/l. Round to four decimal places.

P(x̄ > 6) =

Suppose doctors being very conservative decide to test the woman’s cholesterol level a third time and average the three values. Find the probability that this woman’s mean cholesterol level for the three tests is above 6 mmol/l. Round to four decimal places.

P(x̄ > 6) =

Answer #1

The mean cholesterol levels of women age 45-59 in Ghana,
Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is
1.0 mmol/l (Lawes, Hoorn, Law & Rodgers, 2004). Assume that
cholesterol levels are normally distributed. a.) State the random
variable. b.) Find the probability that a woman age 45-59 in Ghana
has a cholesterol level above 6.2 mmol/l (considered a high level).
c.) Suppose doctors decide to test the woman’s cholesterol level
again and average the two values. Find...

In the United States, males between the ages of 40 and 49 eat on
average 103.1 g of fat every day with a standard deviation of 4.32
g ("What we eat," 2012).
Assume that the amount of fat a person eats is normally
distributed. a.) State the random variable.
b.) Find the probability that a man age 40-49 in the U.S. eats
more than 110 g of fat every day.
c.) Find the probability that a man age 40-49 in...

1. The mean cholesterol levels of women age 45-59 in Ghana,
Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is
1.0 mmol/l. Assume that cholesterol levels are normally distributed
and a random sample of 25 women are selected.
It is possible with rounding for a probability to be
0.0000.
a) Identify the individual, variable, type of variable and the
random variable X in the context of this problem.
The individual is _____
Select an answer:
(a) 25 randomly...

Suppose that are creatine kinase levels among healthy males are
normally distributed with a standard deviation of 22 units/L
research shows that exactly 5% of the healthy males have a creatine
kinase level above 151 units / L what is the mean creatine level in
healthy males? carry your intermediate computations to at least
four decimal places. round your answer to one decimal place.

1) Suppose a random variable, x, arises from a binomial
experiment. Suppose n = 6, and p = 0.11.
Write the probability distribution. Round to six decimal places,
if necessary.
x
P(x)
0
1
2
3
4
5
6
Find the mean.
μ =
Find the variance.
σ2 =
Find the standard deviation. Round to four decimal places, if
necessary.
σ =
2) Suppose a random variable, x, arises from a binomial
experiment. Suppose n = 10, and p =...

Suppose that blood chloride concentration (mmol/L) has a normal
distribution with mean 105 and standard deviation 5.
(a)
What is the probability that chloride concentration equals 106?
Is less than 106? Is at most 106? (Round your answers to four
decimal places.)
equals 106less than 106at most 106
(b)
What is the probability that chloride concentration differs from
the mean by more than 1 standard deviation? (Round your answer to
four decimal places.)
Does this probability depend on the values...

X ~ N(60, 11). Suppose that you form random samples of 25 from
this distribution. Let X be the random variable of averages. Let ΣX
be the random variable of sums.
Part (b) Give the distribution of X. (Enter an exact number as
an integer, fraction, or decimal.) X ~ ,_____ (______, _____)
Part (c) Find the probability. (Round your answer to four
decimal places.) P(X < 60) =
Part (d) Find the 20th percentile. (Round your answer to two...

Use the following information for the next four
problems. Suppose that the cholesterol levels of adult
American women can be described by a normal model with a mean of
188 mg/dL and a standard deviation of 24 mg/dL.
Which one of the following intervals will contain the central
95% of cholesterol levels?
a.
116 to 260
b.
164 to 212
c.
140 to 236
d.
186 to 190
5 points
QUESTION 4
What percent of adult American women will...

Suppose that the mean value of interpupillary distance (the
distance between the pupils of the left and right eyes) for adult
males is 65 mm and that the population standard deviation is 5 mm.
(a) If the distribution of interpupillary distance is normal and a
random sample of n = 25 adult males is to be selected, what is the
probability that the sample mean distance x for these 25 will be
between 63 and 66 mm? (Round all your...

Suppose that the mean value of interpupillary distance (the
distance between the pupils of the left and right eyes) for adult
males is 65 mm and that the population standard deviation is 5
mm.
(a) If the distribution of interpupillary distance is normal and
a random sample of n = 25 adult males is to be selected,
what is the probability that the sample mean distance x
for these 25 will be between 63 and 67 mm? (Round all your...

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