Question

There are six red balls and three green balls in a box. If we
randomly select 3 balls from the box ** without
replacement**, how likely do we observe one green
ball?

Group of answer choices

The probability is between 0.0 and 0.2.

The probability is between 0.6 and 0.8.

The probability is between 0.2 and 0.4.

The probability is between 0.8 and 1.0.

The probability is between 0.4 and 0.6.

Answer #1

There are six red balls and three green balls in a box. If we
randomly select 3 balls from the box with replacement, and let X be
number of green balls selected. So, X ~ Binomial [n=3, p=1/3] Use R
to find the following probabilities and answers. A) How likely do
we observe exactly one green ball? B) Find P[X<=2]. C) Find the
second Decile (the 20th percentile). D) Generating 30 random
observations from Bin(n,p) distribution, where n=3 & p=1/3....

There are six red balls and three green balls in a box. If we
randomly select 3 balls from the box with replacement, and let X be
number of green balls selected. So, X ~ Binomial [n=3, p=1/3] Use R
to find the following probabilities and answers. A) How likely do
we observe exactly one green ball? B) Find P[X<=2]. C) Find the
second Decile (the 20th percentile). D) Generating 30 random
observations from Bin(n,p) distribution, where n=3 & p=1/3....

Box 1 contains 4 red balls, 5 green balls and 1 yellow ball.
Box 2 contains 3 red balls, 5 green balls and 2 yellow
balls.
Box 3 contains 2 red balls, 5 green balls and 3 yellow
balls.
Box 4 contains 1 red ball, 5 green balls and 4 yellow balls.
Which of the following variables have a binomial
distribution?
(I) Randomly select three balls from Box 1 with replacement. X =
number of red balls selected
(II) Randomly...

A box contains one yellow, two red, and three green balls. Two
balls are randomly chosen without replacement. Define the following
events:
A:{ One of the balls is yellow }
B:{ At least one ball is red }
C:{ Both balls are green }
D:{ Both balls are of the same color }
Find the following conditional probabilities:
P(B\Ac)=
P(D\B)=

Suppose you have a box with 10 red balls, 4 green balls, and 6
blue balls. Answer the following questions. Think about the
questions below. They look similar, but how are they different?
a) You randomly select two balls from the box. What is the
probability of selecting two red balls?
b) Suppose you are asked to draw a ball, return whatever you
picked, and draw another ball. This is called sampling with
replacement. What is the probability of selecting...

2. Box A contains 10 red balls, and 15 green balls. Box B
contains 12 red balls and 17 balls
green. A ball is taken randomly from box A and then returned to box
B.
From box B a random ball is drawn.
a) Determine the chance that two green balls are taken.
b) Determine the chance that 1 red ball is drawn and 1 green ball
is taken

In a box of 6 red and 4 green balls, 3 balls are selected at
random without replacement. Find the probability distribution of
the number of red balls. *

A box contains 4 red balls, 3 yellow balls, and 3 green balls.
You will reach into the box and blindly select a ball, take it out,
and then place it to one side. You will then repeat the experiment,
without putting the first ball back. Calculate the probability that
the two balls you selected include a yellow one and a green
one.

A box has 8 red, 5 yellow, and 7 green balls. If three balls are
drawn at random with replacement, the probability that two balls
are yellow or green is

An urn contains five blue, six green and seven red balls. You
choose five balls at random from the urn, without replacement (so
you do not put a ball back in the urn after you pick it), what is
the probability that you chose at least one ball of each
color?(Hint: Consider the events: B, G, and R, denoting
respectively that there are no blue, no green and no red balls
chosen.)

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