Two marbles are drawn without replacement from a box with 3
white, 2 green, 2 red, and 1 blue marble. Find the probability that
both marbles are white.
Solution :
Number of white marbles = 3
Number of green marbles = 2
Number of red marbles = 2
Number of blue marbles = 1
Total number of marbles = 3+2+2+1 = 8
Two marbles are drawn without replacement.
We have to find the probability that both marbles are white.
Probability that first drwan marble is white = number of white marbles/total number of marbles
Probability that first drwan marble is white = 3/8
Now, since marbles are drawn without replacement and one white marble is already drawn, therefore now we have total 7 marbles in which there are two white marbles.
Probability that second drawn marble is white = 2/7
Using the multiplication theorem of probability we shall get the probability that both marbles are white.
Hence, probability that both marbles are white = (3/8) × (2/7) = 3/28
The probability that both marbles are white is 3/28.
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