A fair 10-sided die is rolled 122 times. Consider the event A = {the face 6 comes up at most 2 times}. |
(a) | Find the normal approximation for P(A) without the continuity correction. |
(b) | Find the normal approximation for P(A) with the continuity correction. |
(c) | Find the Poisson approximation for P(A). |
Hi,
Given that 10sided fair sie rolled 122 times
Then n= 122
Probability of face 6 comes up = 1/10
p= 1/10=0.1
Normal approximation→
Mean( u)= 122*0.1=12.2
Standard deviation (s)=√(npq)=3.313608
(a)
Probability of face come up at most 2 time
=Prob(x≤2)
=Prob(z≤(2-12.2)/3.313608)
=Prob(z<-3.078216)
=0.0010
(b)
Probability of face come up at most 2 time
=Prob(x≤2)
=Prob(x<2.5). (Continuity correction factor)
Z score= (x-u)/s=(2.5-12.2)/3.313608=-2.9273
=Prob(z<-2.9273)
=0.0017
Que(c)
Lamda= n*p= 122*0.1= 12.2
P(x=x)= exp(-lamda)*(lamda)^x/x!
=Prob(x≤2)
=0.00037
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