The gas bills in March is normally distributed with a mean of $84, and a standard deviation of $16.
What percent of homes have a gas bills between $ 50 and $ 60?
Solution :
Given that,
mean = = 84
standard deviation = = 16
P ( 50 < x < 60 )
P ( 50 - 84 / 16) < ( x - / ) < ( 60 - 84 / 27)
P ( - 34 / 16 < z < - 24 / 16 )
P (-2.12 < z < -1.5)
P ( z < - 1.5 ) - P ( z < -2.12)
Using z table
= 0.0668 - 0.0170
= 0.0498
Probability = 0.0498 = 4.98%
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