Question

You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05.

      Ho:p=0.76Ho:p=0.76
      Ha:p≠0.76Ha:p≠0.76

You obtain a sample of size n=624n=624 in which there are 448 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.

What is the critical value for this test? (Report answer accurate to three decimal places.)
critical value = ±±

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

The test statistic is...

in the critical region

not in the critical region

This test statistic leads to a decision to...

reject the null

accept the null

fail to reject the null

As such, the final conclusion is that...

There is sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.76.

There is not sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.76.

The sample data support the claim that the population proportion is not equal to 0.76.

There is not sufficient sample evidence to support the claim that the population proportion is not equal to 0.76.

Answer 1

Ho:p=0.76

vs
Ha:p≠0.76

the critical value for this test
critical value = ±1.96

by using =NORMSINV(1-(0.05/2))....................Excel command.

We can use here z table for z critical value also.

the test statistic for this sample
test statistic

=-2.462

P value is 0.0138

P value by using =2*NORMSDIST(-2.462)

The test statistic is...

in the critical region

This test statistic leads to a decision to...

reject the null

There is sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.76.