True or False: a.) Variance is the mean of the squared deviation score. b.) For any population, a z-score of +1.00 corresponds to a location above the mean by one standard deviation. c.) In a distribution with s=8, a score of X=64 corresponds to z=-.50. The mean for this sample will be M=60. d.) Transforming X values into z-scores will not change the shape of the distribution. e.) One advantage of transforming X values into z-scores is that the transformation always creates a normal shaped distribution. f.) It is possible for more than half of the scores in a distribution to have values greater than the mean. g.) A distribution with a mean u=50 and a median of 70 probably is positively skewed.
Solution:-
a) True- Variance is the mean of the squared deviation score.
b) True - For any population, a z-score of +1.00 corresponds to a location above the mean by one standard deviation.
c) False - In a distribution with s = 8, a score of X = 64 corresponds to z =-.50. The mean for this sample will be M = 60.
x = 64
By applying normal distruibution:-
z = 0.50
Hence z is not equal to - 0.50.
d) True - Transforming X values into z-scores will not change the shape of the distribution.
e) False - One advantage of transforming X values into z-scores is that the transformation always creates a normal shaped distribution.
f) True - It is possible for more than half of the scores in a distribution to have values greater than the mean.
g) False - A distribution with a mean u=50 and a median of 70 probably is positively skewed.
In a positively skewed distribution the median is less than the mean.
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