Question

The weights of steers in a herd are distributed normally. The variance is 40,000 and the mean steer weight is 900lbs. Find the probability that the weight of a randomly selected steer is between 1160 and 1279lbs. Round your answer to four decimal places.

Answer 1

Standard deviation = =200

This is a normal distribution question with

This implies that

P(1160.0 < x < 1279.0) = P(1.3 < z < 1.895) = P(Z < 1.895) - P(Z < 1.3)

P(1160.0 < x < 1279.0) = 0.9709 - 0.9032

P(1160.0 < x < 1279.0) = 0.0678

PS: you have to refer z score table to find the final probabilities.

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