Question

The Dean of Students at a large university wanted to estimate the proportion of students who are willing to report cheating by fellow students.

So, her staff surveyed 172 students currently enrolled in the introduction to biology class. The students were asked, “Imagine that you witness

two students cheating on a quiz. Would you tell the professor?” 19 of the surveyed students responded “yes.”

- Using these data, calculate a 95% confidence interval for the proportion of all students at the university that would report cheating.
- Interpret the confidence interval in a sentence.
- Is it actually appropriate to use these data to estimate the proportion of all students at the university that would report cheating? Why or why not? (Hint: sampling.)

Answer #1

A university dean is interested in determining the proportion of
students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 118 of them are receiving financial aid.
Use a 98% confidence interval to estimate the true proportion of
students on financial aid.

A university dean is interested in determining the proportion of
students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 122 of them are receiving financial aid.
Use a 95% confidence interval to estimate the true proportion of
students who receive financial aid.

A university dean is interested in determining the proportion of
students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 118 of them are receiving financial aid. If
the dean wanted to estimate the proportion of all students
receiving financial aid to within 1% with 98% reliability, how many
students would need to be sampled?
Select one: A. 132 B. 5637 C. 13,133 D. 3177

A university dean is interested in determining the proportion of
students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 118 of them are receiving financial aid. If
the dean wanted to estimate the proportion of all students
receiving financial aid to within 3% with 99% reliability, how many
students would need to be sampled?
Please show al work on how you got the answer.

1. A university Dean is interested in determining the proportion
of students who receive
some sort of financial aid. Rather than examine the records for all
students, the dean randomly selects
200 students and finds that 118
of them are receiving financial aid. By hand, and using formulas
for the
“Margin of Error” (i.e. not calculator confidence interval), find a
98% confidence interval to estimate
the true proportion of students on financial aid. (Use 3 decimal
places for proportions.)
2....

1.) A university dean is interested in determining the
proportion of students who receive some sort of financial aid.
Rather than examine the records for all students, the dean
randomly selects 200 students and finds that 118 of them are
receiving financial aid. Use a 95% confidence interval to estimate
the true proportion of students who receive financial aid.
a.) 0.59+/-0.068
b.) 0.59+/-0.005
c.) 0.59+/-0.002
d.)0.59+/-0.474
2.)
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College Smokers
We are interested in estimating the proportion of students at a
university who smoke. Out of a random sample of 200 students from
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( , )
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