An individual diagnosed with lung cancer has a 70% chance of surviving the first year after diagnosis. Find the probability that out of 200 lung cancer patients observed, the probability of survival is more than 150.
Solution :
Given that,
Using binomial distribution,
= n * p = 200 * 0.70 = 140
= n * p * q = 200 * 0.70 * 0.30 = 6.48074
Using continuity correction ,
P(x > 150.5) = 1 - P(x < 150.5)
= 1 - P((x - ) / < (150.5 - 140) / 6.48074)
= 1 - P(z < 1.62)
= 0.0526
Probability = 0.0526
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