Question

An individual diagnosed with lung cancer has a 70% chance of surviving the first year after diagnosis. Find the probability that out of 200 lung cancer patients observed, the probability of survival is more than 150.

Answer #1

Solution :

Given that,

Using binomial distribution,

= n * p = 200 * 0.70 = 140

= n * p * q = 200 * 0.70 * 0.30 = 6.48074

Using continuity correction ,

P(x > 150.5) = 1 - P(x < 150.5)

= 1 - P((x - ) / < (150.5 - 140) / 6.48074)

= 1 - P(z < 1.62)

= **0.0526**

**Probability = 0.0526**

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