Suppose that you sample 28 high school baseball pitchers in one country and find that they have a mean fastball pitching speed of 80.5mph with a standard deviation of 5.2 mph.
a. find a point estimate for the mean fastball pitching speed of all high school baseball pitchers in the country.
b. find a 99% confidence interval for the mean fastball pitching speed of all high school baseball pitchers in the country.
n=
x bar=
s or sigma value=
z or t value=
df (of none, type NA=
error=
LCL=
UCL=
Here, the sample size , n = 28
the sample mean , = 80.5
sample standard deviation , s = 5.2
a) a point estimate for the mean fastball pitching speed of all high school baseball pitchers in the country is the sample mean.
Therefore , point estimate = 80.5
b)We have to find a 99% confidence interval.
We use the t distribution.
Degrees of freedom = n - 1 = 27
Using the t critical values table, at 99% confidence level and df = 27 , the critical value is , t = 2.77
The confidence interval is = t*s/n
= 80.5 2.77 * 0.98
= 80.5 2.723
= (77.78 , 83.22)
LCL = 77.78
UCL = 83.22
error = 2.723
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