Question

Supermarkets throughout the United States sell an average of 460 quarts of milk/day. Over a sample of 36 days chosen at random, a supermarket sells an average of 470 quarts/day with a standard deviation of 20 quarts. At the 0.05 level of significance, does the store sell more milk than the national average?

a. State null hypothesis

b. State alternative hypothesis

c. Is this a one or two tail test? why?

d. Will you conduct a t-test or z-test? why?

e. What is (are) the critical value(s)?

f. What is the decision rule?

g. calculate the statistic

h. What is your decision regarding null hypothesis and why?

i. Interpretation of the results

Answer #1

Supermarkets throughout the United States sell an average of 460
quarts of milk/day with a standard deviation of 20 quarts. Over a
sample of 36 days chosen at random a supermarket sells an average
of 470 quarts/day. At the 0.05 level of significance, does the
store sell more milk than the national average? a) what is the
research problem? (b) state null and alternative hypothesis (c) It
this one or two tailed test? why? (d) what is the critical value?...

The mean income per person in the United States is $38,000, and
the distribution of incomes follows a normal distribution. A random
sample of 13 residents of Wilmington, Delaware, had a mean of
$48,000 with a standard deviation of $9,200. At the 0.100 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.100 significance level....

The mean income per person in the United States is $39,500, and
the distribution of incomes follows a normal distribution. A random
sample of 16 residents of Wilmington, Delaware, had a mean of
$45,500 with a standard deviation of $9,800. At the 0.010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.010 significance level....

The mean income per person in the United States is $45,000, and
the distribution of incomes follows a normal distribution. A random
sample of 17 residents of Wilmington, Delaware, had a mean of
$55,000 with a standard deviation of $8,500. At the 0.100 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.100 significance level....

The mean income per person in the United States is $37,500, and
the distribution of incomes follows a normal distribution. A random
sample of 12 residents of Wilmington, Delaware, had a mean of
$46,500 with a standard deviation of $9,000. At the 0.010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.010 significance level....

The mean income per person in the United States is $37,500, and
the distribution of incomes follows a normal distribution. A random
sample of 12 residents of Wilmington, Delaware, had a mean of
$46,500 with a standard deviation of $9000. At the .010 level of
significance, is that enough evidence to conclude that residents of
Wilmington, Delaware, have more income than the national
average?
(a) State the null hypothesis and the alternate hypothesis.
H0: u is less than or equal...

The manufacturer of a new cigarette claims that the average tar
content per cigarette is 10.0 mg. The US Center for Smoking Research believes
the tar content percigarette is greater than 10 mg and wishes to conduct a study to
support their claim. Theytake a random sample of 25 cigarettes from the production line and
find an average of 10.20mg of tar/cigarette and a standard deviation of .5 mg. Can the
manufacturer’s claim berefuted at the 0.01 level of significance?A....

this is a z test Jane parks at the same meter every day she goes
to work. Lately she has been getting parking tickets because the
time has expired on the meter. She has been putting in the same
amount of money but feels that she has been getting less time on
the meter. Before she complains to the city, she decides to collect
some data to try to convince the city to fix the meter. One quarter
is supposed...

Question #5 – Chi Squared Testing
This is Part B
I) Milk products are an
important source of calcium and vitamin D, nutrients that play an
essential role in maintaining bone health and preventing
osteoporosis. However, most milk products also contain lactose,
which a large proportion of the world’s population has trouble
digesting.
http://www.osteoporosis.ca/wp-content/uploads/2017-05-31-COPING-Lactose-Intolerance-FINAL.pdf
In fact, it has been estimated that seven million Canadians
suffer from lactose intolerance. There are many factors affecting
how populations adapt and react to lactose...

Wild irises are beautiful flowers found throughout the United
States, Canada, and northern Europe. This problem concerns the
length of the sepal (leaf-like part covering the flower) of
different species of wild iris. Data are based on information taken
from an article by R. A. Fisher in Annals of Eugenics
(Vol. 7, part 2, pp. 179 -188). Measurements of sepal length in
centimeters from random samples of Iris setosa (I),
Iris versicolor (II), and Iris virginica (III)
are as follows...

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