In a survey, 32 people were asked how much they spent on their
child's last birthday gift. The results were roughly bell-shaped
with a mean of $48 and standard deviation of $20. Construct a
confidence interval at a 90% confidence level.
Give your answers to one decimal place.
Solution :
t /2,df = 1.696
Margin of error = E = t/2,df * (s /n)
= 1.696 * (20 / 32)
Margin of error = E = 6.0
The 90% confidence interval estimate of the population mean is,
- E < < + E
48 - 6 < < 48 + 6
42.0 < < 54.0
(42.0 , 54.0)
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