Cigarets randomlyselected from 2 popular brands are analyzed to determine their nicotine content (in mg). The results are as follows.
Brand A: n1=10 x1=32.1 S1=4.1
Brand B: n2=15 x2=34.9 S2=3.3
Tets the a=0.05 , whether the average nicotine of brand A is less than standard B
So:
its t test for difference in means assuming unequal variances,
H0:
H1:
alpha=0.05
test statitsic:
t=x1-x2/sqrt(n1-1)s1^2+(n2-1)s2^2/n1+n2-2(1/n1+1/n2)
t=(32.1-34.9)/sqrt((10-1)4.1^2+(15-1)3.3^2/10+15-2(1/10)+(1/15))
t=-1.805
using the p value approach,the p vaue is p=0.0447, and since
p<0.05
Reject Null hypothesis
Accept alternatiev Hypothesis.
Conclusion:
There is suffcicient evidence at 5% level of significance to
conclude that he average nicotine of brand A is less than standard
B
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