10. For a particular scenario, we wish to test the hypothesis H0 : p = 0.52. For a sample of size 50, the sample proportion p̂ is 0.42. Compute the value of the test statistic zobs. (Express your answer as a decimal rounded to two decimal places.)
4. For a hypothesis test of
H0 : μ = 8
vs.
H0 : μ > 8,
the sample mean of the data is computed to be 8.24. The population standard deviation is unknown; the sample standard deviation is computed, and its value is 0.29. These sample statistics are based on a sample size of 19. It is assumed that the underlying population is normally distributed. Which of the following would be the distribution of the test statistic in this scenario?
a |
The standard normal distribution |
|
b |
The t-distribution with 18 degrees of freedom |
|
c |
The t-distribution with 19 degrees of freedom |
|
d |
The t-distribution with 8 degrees of freedom |
6. For a sample of 37 observations, the sample mean X̄ and the sample standard deviation s are used to construct a 95% t-based confidence interval for the population mean mu. If the confidence interval is (3.48, 4.32), then which of the following statements is NOT true?
a |
The value of X̄ is 3.9. |
|
b |
The t-score used in constructing the confidence interval is 2.028. |
|
c |
There is a 95% probability that the true value of μ is between 3.48 and 4.32. |
|
d |
The conclusion of a t-based test of H0 : μ = 3.75 vs. H1 : μ ≠ 3.75 would be to fail to reject. |
10. Zobs=(-p)/(√p(1-p)/n)
=(0.42-0.52)/(√0.52*0.48/50)= -1.415
So required z statistic is -1.415
4. Since population SD is unknown, for the test of the true mean value here, we would use a tn-1 distribution. That is a t test with df: n-1= 19-1= 18
So option b is correct.
6. Confidence interval is given as:
Sample mean +-Margin of error
So the sample mean = (4.32+3.48)/2 = 3.9
So option a is correct
t-score should be t0.025,n-1 ie t0.025,36= 2.028
So option b is correct.
We can also see that u=3.75 is contained in the CI above. So option d is also correct, we fail to Reject H0.
Now option c is false. From the CI we can only say that we are 95% confident that the true mean is contained in the interval above, we cannot say the probability is 0.95
So option c is false.
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