Question

Paired T confidence interval: μD = μ1 - μ2 : Mean of the difference between Male...

Paired T confidence interval:


μD = μ1 - μ2 : Mean of the difference between Male Population and Female Population
90% confidence interval results:

Difference

Mean

Std. Err.

DF

L. Limit

U. Limit

Male Population - Female Population

-4443.9378

721.71083

594

-5632.9008

-3254.9748

Why is the above data paired? Interpret and state your confidence Interval, and based on your confidence interval is there a significant difference in male and female populations; if so what is it and how do you know?

Homework Answers

Answer #1

the element in the male population is matched to the element selected from female population hence its a paired t test.we are 90% confident that the true difference in  Male Population and Female Population lies in between

-5632.9008 and -3254.9748.

Ho:mu1-mu2=0

Ha:mu1-mu2 not=0

Fail to reject Ho as the 90% confidence intrval do not contain zero

There is no significant difference in male and female populations, since the 90% confidence interval for difference between Male Population and Female Population do not contain 0.

.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the...
Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d=x1-x2. A 95% confidence interval for μd using the paired data in the following table: Case Situation 1 Situation 2 1 77 87 2 81 86 3 95 91 4 61 79 5 71 77 6 72 62...
Use the t-distribution to find a confidence interval for a difference in means μ1-μ2 given the...
Use the t-distribution to find a confidence interval for a difference in means μ1-μ2 given the relevant sample results. Give the best estimate for μ1-μ2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ1-μ2 using the sample results x¯1=81.1, s1=10.3, n1=35 and x¯2=67.1, s2=7.9, n2=20 Enter the exact answer for the best estimate and round your answers for the margin of...
Find the 95% confidence interval for estimating μd based on these paired data and assuming normality....
Find the 95% confidence interval for estimating μd based on these paired data and assuming normality. (Give your answers correct to one decimal place.) Before 43 42 67 54 59 55 After 42 50 34 54 30 58 Lower Limit Upper Limit
Find the 99% confidence interval for estimating μd based on these paired data and assuming normality....
Find the 99% confidence interval for estimating μd based on these paired data and assuming normality. (Give your answers correct to one decimal place.) Before 42 65 52 57 58 48 After 30 43 48 32 30 50 Lower Limit Upper Limit
A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has...
A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has results in the following output: one sample proportion summary confidence interval: p: proportion of success method:standard-wald 90% confidence interval results: proportion: p count:1136 total:1803 sample prop: 0.63006101 std. edrr.: 0.011369948 l. limit: 0.61135911 u. limit: 0.6487629 a. Identify the values for n, p, ˆ q, ˆ and E. b. Write a statement that interprets the 90% confidence interval
A random sample of 40 adults with no children under the age of 18 years results...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.04 hours, with a standard deviation of 2.26 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.28 ​hours, with a standard deviation of 1.73 hours. Construct and interpret a 90​% confidence interval for the mean difference in leisure time between adults with no...
Find the 95% confidence interval for the difference between two means based on this information about...
Find the 95% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 17 40 26 2 30 26 27 Lower Limit Upper Limit You may need to use the appropriate table in Appendix B to answer this question.
Consider the following data drawn independently from normally distributed populations: x1 = 34.4 x2 = 26.4...
Consider the following data drawn independently from normally distributed populations: x1 = 34.4 x2 = 26.4 σ12 = 89.5 σ22 = 95.8 n1 = 21 n2 = 23 a. Construct the 90% confidence interval for the difference between the population means. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval is__________ to__________. b. Specify the competing hypotheses in order to determine...
Chapter 6, Section 4-CI, Exercise 191 Use the t-distribution to find a confidence interval for a...
Chapter 6, Section 4-CI, Exercise 191 Use the t-distribution to find a confidence interval for a difference in means μ1- μ 2 given the relevant sample results. Give the best estimate for μ1- μ 2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ1- μ 2 using the sample results X̄1=5.4 ,s1=3.0, n1 = 11. And X̄2=4.3 ,s2= 3.1, n2= 8...
use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the...
use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the population mean. justify your decision. if neither distribution can be used explain why. interpret the results. In a random sample of 24 mortgage institutions, the mean interest rate was 3.62% and the standard deviation was 0.41% Assume the interest rates are normally distributed. which distribution should be used to construct the confidence interval? The 90% confidence interval is? Interpret the results
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT