In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time college students who earn a bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a 0.03 margin of error and use a confidence level of 99%. Complete parts (a) through (c) below. . Assume prior studies have shown that about 45% of full-time students earn bachelor's degrees in four years or less
n=?
Solution:
Given that,
= 0.45
1 - = 1 - 0.45 = 0.55
margin of error = E = 0.03
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z / 2) / E)2 * * (1 - )
= (2.576 / 0.03)2 * 0.45 * 0.55
=1824.60
= 1825
n = sample size = 1825
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