A soft drink manufacturer wishes to know how many soft drinks adults drink each week. They want to construct a 95% confidence interval with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 3.1 soft drinks per week and found the variance to be 0.49. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.
Solution :
Given that,
variance = 2 = 0.49
standard deviation = = 0.7
margin of error = E = 0.08
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = n = ((Z/2 * ) / E)2
= ((1.96 * 0.7) / 0.08)2
= 294.1225 = 295
Sample size = 295
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