Question

Please interpret the output below. What type of test was used and why? Are energy costs...

Please interpret the output below. What type of test was used and why? Are energy costs lower for LEED-certified buildings in this output? These data have an effect size of d = .39. How does that add to your interpretation of the results?

Yearly Energy Costs LEED- Certified Buildings

(in thousands of $)

Yearly Energy Costs non-LEED- Certified Buildings

(in thousands of $)

Mean

18.22

21.46

Variance

1548.27

1318.33

Observations

60

55

Hypothesized Mean Difference

0

df

73

t Stat

-1.678

P(T<=t) one-tail

0.048

t Critical one-tail

1.667

P(T<=t) two-tail

0.096

t Critical two-tail

1.993

Homework Answers

Answer #1

Here student independent sample 't' test was used.

Reason: Here two independent groups are there and also we are testing mean energy costs between two groups.

IT IS A ONE - TAILED TEST

Here research hypothesis is Are energy costs lower for LEED-certified buildings in this output?

Ho: mean difference = 0 Vs. H1: mean1<mean2

Therefore t-statistic = -1.678 and one tailed p = 0.048

Here p <0.05 hence we reject Null hypothesis.

Conclusion: There was an enough evidence that the energy costs lower for LEED-certified buildings

Here effect size of d = .39, it indicates medium effect i.e. likely to be different in the means.

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