Question

Suppose that the heights of adult women in the United States are normally distributed with a...

Suppose that the heights of adult women in the United States are normally distributed with a mean of 64 inches and a standard deviation of 2.2 inches. Jennifer is taller than 80% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Height calculation by z- score.

Here Jennifer is 65.8 inch taller.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose that the heights of adult men in the United States are normally distributed with a...
Suppose that the heights of adult men in the United States are normally distributed with a mean of 69 inches and a standard deviation of 3 inches. What proportion of the adult men in United States are at least 6 feet tall? (Hint: 6 feet =72 inches.) Round your answer to at least four decimal places.
Heights of men and women in the U.S. are normally distributed. Recent information shows: Adult men...
Heights of men and women in the U.S. are normally distributed. Recent information shows: Adult men heights:    µ = 69.6 inches with σ = 3 inches. Adult women heights: µ = 64.1 inches with σ = 2.7 inches. A. 6.62 B. 0.1414 C. 0.8002 D. 5.75 E. 65 F. 79       -       A.       B.       C.       D.       E.       F.    If a woman is selected at random from...
heights of adult American women are normally distributed with an average of 5 feet 4 inches...
heights of adult American women are normally distributed with an average of 5 feet 4 inches (64 inches) and standard deviation 2.5 inches. Whats the proportion of adult American women are taller than 6 feet? I have no idea how to do this A) 99.9% B) 0.1% C) 50% D) 0.032%
According to the National Health Survey, the heights of adult males in the United States are...
According to the National Health Survey, the heights of adult males in the United States are normally distributed with mean 69.0 inches and a standard deviation of 2.8 inches. (a) What is the probability that an adult male chosen at random is between 66 and 72 inches tall? (Round your answer to five decimal places.) (b) What percentage of the adult male population is more than 6 feet tall? (Round your answer to three decimal places.)
The heights of adult men in America are normally distributed, with a mean of 69.3 inches...
The heights of adult men in America are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.62 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.3 inches and a standard deviation of 2.56 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? z = b) What percentage of men are SHORTER than 6 feet 3 inches?...
The heights of adult men in America are normally distributed, with a mean of 69.3 inches...
The heights of adult men in America are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.66 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.7 inches and a standard deviation of 2.56 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? b) What percentage of men are SHORTER than 6 feet 3 inches? Round to...
The heights of adult men in America are normally distributed, with a mean of 69.7 inches...
The heights of adult men in America are normally distributed, with a mean of 69.7 inches and a standard deviation of 2.65 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.2 inches and a standard deviation of 2.55 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? b) What percentage of men are SHORTER than 6 feet 3 inches? Round to...
The heights of adult men in America are normally distributed, with a mean of 69.8 inches...
The heights of adult men in America are normally distributed, with a mean of 69.8 inches and a standard deviation of 2.64 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.4 inches and a standard deviation of 2.54 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? z = b) What percentage of men are SHORTER than 6 feet 3 inches?...
The heights of adult men in America are normally distributed, with a mean of 69.1 inches...
The heights of adult men in America are normally distributed, with a mean of 69.1 inches and a standard deviation of 2.69 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.5 inches and a standard deviation of 2.57 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? b) What percentage of men are SHORTER than 6 feet 3 inches? Round to...
The heights of adult men in America are normally distributed, with a mean of 69.1 inches...
The heights of adult men in America are normally distributed, with a mean of 69.1 inches and a standard deviation of 2.67 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.8 inches and a standard deviation of 2.56 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? z = b) If a woman is 5 feet 11 inches tall, what is...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT