Question

Suppose that the heights of adult women in the United States are normally distributed with a mean of 64 inches and a standard deviation of 2.2 inches. Jennifer is taller than 80% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.

Answer #1

Height calculation by z- score.

Here Jennifer is **65.8 inch** taller.

Suppose that the heights of adult men in the United States are
normally distributed with a mean of 69 inches and a standard
deviation of
3 inches. What proportion of the adult men in United States are
at least 6 feet tall? (Hint: 6 feet =72 inches.) Round your answer
to at least four decimal places.

Heights of men and women in the U.S. are normally distributed.
Recent information shows:
Adult men heights: µ = 69.6 inches with σ = 3
inches.
Adult women heights: µ = 64.1 inches with σ = 2.7 inches.
A.
6.62
B.
0.1414
C.
0.8002
D.
5.75
E.
65
F.
79
- A.
B. C.
D. E.
F.
If a woman is selected at random from...

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The heights of adult women in America are also normally
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a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z =
b) What percentage of men are SHORTER than 6 feet 3 inches?...

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distributed, with a mean of 69.3 inches and a standard deviation of
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normally distributed, but with a mean of 64.7 inches and a standard
deviation of 2.56 inches.
a) If a man is 6 feet 3 inches tall, what is his
z-score (to two decimal places)?
b) What percentage of men are SHORTER than 6 feet 3
inches? Round to...

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with a mean of 69.7 inches and a standard deviation of 2.65 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.2 inches and a standard
deviation of 2.55 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
b) What percentage of men are SHORTER than 6 feet 3 inches?
Round to...

The heights of adult men in America are normally distributed,
with a mean of 69.8 inches and a standard deviation of 2.64 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.4 inches and a standard
deviation of 2.54 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z =
b) What percentage of men are SHORTER than 6 feet 3 inches?...

The heights of adult men in America are normally distributed,
with a mean of 69.1 inches and a standard deviation of 2.69 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.5 inches and a standard
deviation of 2.57 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
b) What percentage of men are SHORTER than 6 feet 3 inches?
Round to...

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with a mean of 69.1 inches and a standard deviation of 2.67 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.8 inches and a standard
deviation of 2.56 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z =
b) If a woman is 5 feet 11 inches tall, what is...

The heights of adult men in America are normally distributed
with a mean of 69.5 inches and a standard deviation of 2.65 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.1 inches and a standard
deviation of 2.58 inches. (a) If a man is 6 feet 3 inches tall,
what is his z-score (to two decimal places)? z = (b) If a woman is
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