Four different paints are advertised as having the same drying time. To check the manufacturers' claims, five samples were tested for each of the paints. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. Conduct an analysis to see whether the mean drying time is the same for each type of paint.
Paint 1 | Paint 2 | Paint 3 | Paint 4 |
128 | 144 | 133 | 150 |
137 | 133 | 132 | 142 |
135 | 138 | 137 | 148 |
124 | 146 | 136 | 140 |
145 | 130 | 131 | 153 |
What is the test statistic value from your analysis?
Solution
We will find the test statistic using excel by performing One Way Anova
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Paint 1 | 5.0000 | 669.0000 | 133.8000 | 66.7000 | ||
Paint 2 | 5.0000 | 691.0000 | 138.2000 | 47.2000 | ||
Paint 3 | 5.0000 | 669.0000 | 133.8000 | 6.7000 | ||
Paint 4 | 5.0000 | 733.0000 | 146.6000 | 29.8000 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 546.2000 | 3.0000 | 182.0667 | 4.8422 | 0.0139 | 3.2389 |
Within Groups | 601.6000 | 16.0000 | 37.6000 | |||
Total | 1147.8000 | 19.0000 |
the test statistic value F = 4.8422
P-value = 0.0139
Conclusion : Here P-value = 0.0139 < 0.05 level of significance so we reject the null hypothesis and conclude that the mean drying time is not same for each type of paint.
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