A water supplying company wishes to estimate the average amount that private customers pay per month. A random sample of 25 customers' bills during a given month produced a sample mean of $30, and a sample standard deviation of $5. (So, the current problem differs from the previous. In the previous problem, $5 presented the standard deviation for the whole population, while in these problem, $5 is the standard deviation on; only for a sample of 25 customers.)
a) Without any calculations, do you expect that the 90% confidence interval in the case of the current problem will be wider than that in the previous problem or narrower? Justify the answer.
Yes, the 90% confidence interval in this case of the current problem will be wider than that in the previous problem.
The critical value for this problem is t0.05;24 = 1.711 and for previous problem the critical value is Z0.05 = 1.645.
Also, the sample size is smaller for this problem than the previous one.
So, that is why without doing any calculations we can conclude that the 90% confidence interval in this case of the current problem will be wider than that in the previous problem.
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