Question

We wish to create a 96% confidence interval for the proportion. A sample of 36 gives...

We wish to create a 96% confidence interval for the proportion. A sample of 36 gives a proportion of 0.72. Find the lower value for the confidence interval. Round to 3 decimal places.

Homework Answers

Answer #1

https://drive.google.com/open?id=1LVIRqPX5eaoGNXIcyUu4g8wZNJgerW2X

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
We wish to create a 98% confidence interval for the mean. A sample of 24 gives...
We wish to create a 98% confidence interval for the mean. A sample of 24 gives an average of 72 and a standard deviation of 6.35 . Find the lower value for the confidence interval. Round to 2 decimal places.
We wish to create a 92% confidence interval for the mean given that the standard deviation...
We wish to create a 92% confidence interval for the mean given that the standard deviation is known to be 9.842. A sample of 35 gives an average of 220. Find the Margin of Error. Round to three decimal places.
We wish to create a 90% confidence interval for the Variance given that a sample of...
We wish to create a 90% confidence interval for the Variance given that a sample of 30 has a standard deviation of 2. Find the Lower value for the confidence interval.Round to tenths.
We wish to create a 92% confidence interval for the mean given that the standard deviation...
We wish to create a 92% confidence interval for the mean given that the standard deviation is known to be 34.4. A sample of 34 gives an average of 190. Find the upper value for the confidence interval. Round to tenths.
Create a 90% confidence interval about a sample proportion given that the sample proportion is .61...
Create a 90% confidence interval about a sample proportion given that the sample proportion is .61 and the sample size is 1250.
Confidence Interval Given. Assume I created a 96% confidence interval for the mean hours studied for...
Confidence Interval Given. Assume I created a 96% confidence interval for the mean hours studied for a test based on a random sample of 100 students. The lower bound of this interval was 3 and the upper bound was 16. Assume that when I created this interval I knew the population standard deviation. Using this information, (a) Calculate the width of the interval. (b) Calculate the margin of error for the interval. (c) Calculate the center of the interval. (d)...
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the...
1.A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the confidence interval 0.117 < p < 0.412 to find the point estimate, p ^ . Round answer to 3 decimal places. 2.A confidence interval was constructed to estimate the proportion of people who suffer from seasonal allergy. Use the confidence interval 0.466 < p < 0.54 to find the point estimate, p ^ . Round answer to 3 decimal places. 3.A confidence interval was...
The following gives information about the proportion of a sample that agree with a certain statement....
The following gives information about the proportion of a sample that agree with a certain statement. Use StatKey or other technology to find a confidence interval at the given confidence level for the proportion of the population to agree, using percentiles from a bootstrap distribution. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. Find a confidence interval if, in a random sample of 1000 people, 382 agree, 578 disagree, and 40 can't...
A sociologist wants to construct a 96% confidence interval for the proportion of children aged 5...
A sociologist wants to construct a 96% confidence interval for the proportion of children aged 5 – 11 living in New York who own cell phones. a) A survey by Mediamark Research and Intelligence estimated the nationwide proportion to be 0.20. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.02? b) Estimate the sample size needed if no estimate of the nationwide proportion is given.
Construct a confidence interval of the population proportion at the given level of confidence. x=540, n=1100​,...
Construct a confidence interval of the population proportion at the given level of confidence. x=540, n=1100​, 95​% confidence The lower bound of the confidence interval is _______. ​(Round to three decimal places as​ needed.) The upper bound of the confidence interval is_______. ​(Round to three decimal places as​ needed.)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT