Question

Find the range and standard deviation of the set of data.

220

224

228

232

236

240

244

Answer 1

ANSWER:

Given that,

Find the range and standard deviation of the set of data.

220

224

228

232

236

240

244

Range:

The range is max value - min value

range = 244-220

range = 24

Standard deviation

= x / n = (220+224+228+232+236+240+244)/7 = 1624/7 = 232

standard deviation = s = sqrt( (x-)^2 / (n-1))

=sqrt(((220-232)^2+(224-232)^2+(228-232)^2+(232-232)^2+(236-232)^2+(240-232)^2+(244-232)^2)/(7-1))

= 8.64099

standard deviation = 8.64099

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