Question

The weights in pounds of discarded plastic from a sample of 62 households gave a sample mean of ¯ x = 1.911 lbs. and a standard deviation of s = 1.065 . Using α = .05 , test the claim that the mean weight of discarded plastic from the population of households is greater than 1.8 lbs. Round all values to three decimal places where necessary. State your null and alternative hypothesese. Use \mu for μ . h 0 : h 1 : What is the correct test to use for this hypothesis test? Select an answer What is the P-value for this test? Be sure to write as a decimal and not in scientific notation if it applies. What is your decision? Select an answer Clearly state your conclussion in complete sentences.

Answer #1

Solution :

= 1.8

= 1.911

S =1.065

n = 62

This is the right tailed test .

The null and alternative hypothesis is ,

H0 : = 1.8

Ha : > 1.8

Test statistic = t

= ( - ) / S / n

= (1.911 - 1.8) / 1.065 / 62

= 0.821

Test statistic = t = 0.821

P-value =0.2075

= 0.05

P-value <

0.2075 > 0.05

Fail to reject the null hypothesis .

There is not sufficient evidence to concluded that the population mean μ is greater than 1.8, at the 0.05 significance level.

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