Student Number |
Gender (M = male; F = female; O = other) |
Race (Y = Latinx; N = Other) |
Age (18 years or older) |
GPA (0-4 point scale) |
1 |
M |
Y |
22 |
2.4 |
2 |
O |
Y |
20 |
3.5 |
3 |
F |
Y |
22 |
2.8 |
4 |
M |
Y |
28 |
2.8 |
5 |
F |
Y |
30 |
4.0 |
6 |
M |
Y |
23 |
3.8 |
7 |
M |
N |
18 |
3.2 |
8 |
F |
N |
20 |
3.5 |
9 |
O |
N |
18 |
2.8 |
10 |
M |
N |
20 |
4.0 |
1. The dotplot is:
2. The sample mean = 22.1
3. The sample standard deviation for Age = 4.01
4. df = 10 - 1 = 9
5. The hypothesis being tested is:
H0: µ = 26.2
Ha: µ ≠ 26.2
26.200 | hypothesized value |
22.100 | mean Age |
4.012 | std. dev. |
1.269 | std. error |
10 | n |
9 | df |
-3.231 | t |
.0103 | p-value (two-tailed) |
The p-value is 0.0103.
Since the p-value (0.0103) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that µ ≠ 26.2.
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