Question

A manufacturer of irrigation systems for buildings claimed that their systems are activated at an average...

A manufacturer of irrigation systems for buildings claimed that their systems are activated at an average temperature of a 130 degrees Fahrenheit, but affected customers claim that the systems have not been activated for a while and conclude that the average activation temperature is greater than the one claimed by the manufacturer, which puts people's lives at risk. 9 systems were tested and the average activation temperature was 131.8 degrees. If we assume that the activation temperature follows a normal distribution with a known variance of 1.5 degrees:

a) If the manufacturer's claim is true and the reaction temperature is indeed 130 degrees, what will be the probability of concluding that it is false?

b) If the manufacturer's claim is true, what proportion of the systems will not activate until the temperature reaches a value greater than 130 degrees?

c) A colleague of yours with very little exposure to statistical concepts determines that you will do the test simply by testing 10 systems at random and that you will conclude that the average activation temperature is greater than 130 degrees if the average of the 10 observations is equal to or greater than 130.5 degrees. How likely is this test to make a Type I error?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A manufacturer of sprinkler systems used for fire protection in office buildings claims that the true...
A manufacturer of sprinkler systems used for fire protection in office buildings claims that the true average system-activation temperature is 130o F. A sample of n = 9 systems, when tested, yields a sample average activation temperature of 131.08o F. If the distribution of activation times is normal with standard deviation 1.5o F, does the data contradict the manufacturer’s claim at a significance level of 0.01? Answer this question via the following parts: a) What is the parameter of interest?...
) A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature...
) A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135℉ . To test this claim, you randomly select a sample of 32 systems and find that the mean activation temperature is 133℉ . Assume that the population standard deviation is 3.3℉ . At α=0.05, do we have enough evidence to reject the manufacturer’s claim? (Please write your answers in complete sentences.) Identify the claim and state the Null and Alternate...
2. a. A meteorologist claims that the average high temperature for the month of August in...
2. a. A meteorologist claims that the average high temperature for the month of August in Philadelphia, PA. is 83 degrees Fahrenheit. If the residents of Philadelphia do not believe this to be true, what hypotheses should they test? Ho: u > 83 degrees Fahrenheit vs. Ha: u < 83 degrees Fahrenheit Ho: u = 83 degrees Fahrenheit vs. Ha: u < 83 degrees Fahrenheit Ho: u < 83 degrees Fahrenheit vs. Ha: u > 83 degrees Fahrenheit Ho: u...
A) A slow cooker manufacturer claims that the true average ’Low’ temperature setting for their prod-...
A) A slow cooker manufacturer claims that the true average ’Low’ temperature setting for their prod- ucts is 130◦ C. A sample of 9 slow cookers are tested and the average ’Low’ temperature setting is 131.08◦ C. If the distribution is normal with standard deviation 1.5◦C , does the data contradict the manufacturer’s claim at significance level α = 0.01 ? B) Suppose that in an AB test, we test two website design for an online retailer. The first design...
Q1.(10 pts) The fridge manufacturer claims the average daily electricity consumption of one energy efficient model...
Q1.(10 pts) The fridge manufacturer claims the average daily electricity consumption of one energy efficient model is 0.5 kW.h, the standard deviation of the daily electricity consumption is 0.16 kW.h. For one random sample of 45 fridges, Find the probability that the sample average daily electricity consumption is greater than 0.55 kW.h. Q3.(10 pts) Following the above Q1, the manufacturer recently improved technique and claims that the average daily electricity consumption decreased after the improvement. The suggested average daily electricity...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is larger than the right foot. Here we test this claim on a sample of 10 right-handed adults. The table below gives the left and right foot measurements in millimeters (mm). Test the claim at the 0.01 significance level. You may assume the sample of differences comes from a normally distributed population. Person Left Foot (x) Right Foot (y) difference (d = x − y)...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is larger than the right foot. Here we test this claim on a sample of 10 right-handed adults. The table below gives the left and right foot measurements in millimeters (mm). Test the claim at the 0.01 significance level. You may assume the sample of differences comes from a normally distributed population. Person Left Foot (x) Right Foot (y) difference (d = x − y)...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is larger than the right foot. Here we test this claim on a sample of 10 right-handed adults. The table below gives the left and right foot measurements in millimeters (mm). Test the claim at the 0.05 significance level. You may assume the sample of differences comes from a normally distributed population. Person Left Foot (x) Right Foot (y) difference (d = x − y)...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is larger than the right foot. Here we test this claim on a sample of 10 right-handed adults. The table below gives the left and right foot measurements in millimeters (mm). Test the claim at the 0.05 significance level. You may assume the sample of differences comes from a normally distributed population. Person Left Foot (x) Right Foot (y) difference (d = x − y)...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is...
Foot-Length: It has been claimed that, on average, right-handed people have a left foot that is larger than the right foot. Here we test this claim on a sample of 10 right-handed adults. The table below gives the left and right foot measurements in millimeters (mm). Test the claim at the 0.05 significance level. You may assume the sample of differences comes from a normally distributed population. Person Left Foot (x) Right Foot (y) difference (d = x − y)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT