If light bulbs have lives that are normally distributed with a mean of 2500 hours and a standard deviation of 500 hours, use the 68-95-99.7 rule to approximate the percentage of light bulbs having a life less than 1500
Solution :
Given that,
= 2500
= 500
Using Empirical rule,
P( - 1< X < + 1) = 68%
P( - 2< X < + 2) = 95%
P( - 3< X < + 3) = 99.7%
P(x < 1500) = 0.025 = 2.5%
Get Answers For Free
Most questions answered within 1 hours.