Question

Assume that a sample is used to estimate a population proportion
*p*. Find the 99.9% confidence interval for a sample of size
333 with 163 successes. Enter your answer as an
**open-interval** (*i.e.*, parentheses) using
decimals (not percents) accurate to three decimal places.

Answer #1

**A sample is used to estimate the population proportion
p.**

**We have 163 successes in a sample of 333.**

**Now, we find that**

**The sample proportion is p=163/333=0.489**

**The z-value for 99.9% confidence interval is
z=3.291.**

**The sample size is n=333**

**Now, we know that the formula of confidence interval is
given by**

**So, the required answer is (0.399,0.579).**

1. Assume that a sample is used to estimate a population
proportion p. Find the 80% confidence interval for a sample of size
399 with 303 successes. Enter your answer as an open-interval
(i.e., parentheses) using decimals (not percents) accurate to three
decimal places.
80% C.I. =
2. Assume that a sample is used to estimate a population
proportion p. Find the 80% confidence interval for a
sample of size 315 with 18.1% successes. Enter your answer as an
open-interval...

Assume that a sample is used to estimate a population proportion
p. Find the 99.9% confidence interval for a sample of size 391 with
304 successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.

Assume that a sample is used to estimate a population proportion
p. Find the 98% confidence interval for a sample of size 194 with
21% successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.

Assume that a sample is used to estimate a population proportion
p. Find the 90% confidence interval for a sample of size 230 with
12% successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.

Assume that a sample is used to estimate a population proportion
p. Find the 98% confidence interval for a sample of size 176 with
114 successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.

Assume that a sample is used to estimate a population proportion
p. Find the 95% confidence interval for a sample of size
395 with 73% successes. Enter your answer as an
open-interval (i.e., parentheses) using
decimals (not percents) accurate to three decimal places.
C.I. =

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size 279 with
16% successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.
C.I. =

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size 321 with
230 successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places. C.I. =

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size 262 with
137 successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.
C.I. =

Assume that a sample is used to estimate a population proportion
p. Find the 98% confidence interval for a sample of size 199 with
52 successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.
C.I. =

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 2 minutes ago

asked 8 minutes ago

asked 10 minutes ago

asked 12 minutes ago

asked 19 minutes ago

asked 23 minutes ago

asked 32 minutes ago

asked 44 minutes ago

asked 47 minutes ago

asked 51 minutes ago

asked 51 minutes ago

asked 57 minutes ago