Question

7 coffees, 4 teas, and 3 hot chocolates are sitting on a counter. If 5 drinks are picked from the counter at random without replacement, what is the probability that at most two teas are chosen.

Answer 1

7 coffees, 4 teas, and 3 hot chocolates are sitting on a counter.

5 drinks are picked at random without replacement.

Probability that at most two teas are chosen= P(A ≤ 2) where A denotes the number of teas selected.

Now, P(A ≤ 2) = P(A=0) + P(A=1) + P(A=2)

Now, there are 10 drinks excluding the teas. and total of 14 drinks

Therefore, P(A ≤ 2) = 0.1259 + 0.4196 + 0.3596 = 0.9051

The probability that at most two teas are chosen is 0.9051