Question

An organization surveyed 1 comma 100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alcoholic​ beverages?" Of the 1 comma 100 adults​ surveyed, 362 indicated that they were total abstainers. Sixty years​ later, the same question was asked of 1 comma 100 adults and 410 indicated that they were total abstainers. Has the proportion of adults who totally abstain from alcohol​ changed? Use the alpha equals 0.05 level of significance. Determine the null and alternative hypotheses. Choose the correct answer below. A. Upper H 0 : p 1 equals 0 versus Upper H 1 : p 1 not equals 0 B. Upper H 0 : p 1 equals p 2 versus Upper H 1 : p 1 greater than p 2 C. Upper H 0 : p 1 equals p 2 versus Upper H 1 : p 1 less than p 2 D. Upper H 0 : p 1 equals p 2 versus Upper H 1 : p 1 not equals p 2 The test statistic z 0 is nothing . ​(Round to two decimal places as​ needed.) The​ P-value is nothing . ​(Round to three decimal places as​ needed.) What is the result of this hypothesis​ test? A. Do not reject the null hypothesis because there is sufficient evidence to conclude that the proportion of adults who totally abstain from alcohol has changed at the alpha equals 0.05 level of significance. B. Reject the null hypothesis because there is sufficient evidence to conclude that the proportion of adults who totally abstain from alcohol has changed at the alpha equals 0.05 level of significance. C. Do not reject the null hypothesis because there is not sufficient evidence to conclude that the proportion of adults who totally abstain from alcohol has changed at the alpha equals 0.05 level of significance. D. Reject the null hypothesis because there is not sufficient evidence to conclude that the proportion of adults who totally abstain from alcohol has changed at the alpha equals 0.05 level of significance.

Answer 1

Conclusion : Reject the null hypothesis because there is sufficient evidence to conclude that the proportion of adults who totally abstain from alcohol has changed at the alpha equals 0.05 level of significance.

Answer - option B